Python Dictionaries part1 - Day 7

Dictionaries store elements in key value pair,we can not append values to dictionary through any function or method ,we can assign using the key, functions like get,clear,del works with dictionary

  
#dictionary can not be accessed vy index,but through key value
films = {"muthu":"one of the movie in which rajini comes in double role",
         "basha":"Don of a don movie,a cult hit",
         "enthiran":"rajini's scifi movie",
         "murattu kalai":"movie taken in paganeri"}
print(films)
print(films["murattu kalai"])
#to add a new value to dictionay we dont have a method or function,but we can assign like the below one
films["kaala"]="more like a basha 2,april 27th - 2018 release"
print(films)
#if we use the same key and assign it will update instead of creating new element
films["kaala"]="probably thalaivars gonna be biggest hit"
print(films)
#similarly it will take the last set of key,value combination if there is any duplicate
films = {"muthu":"one of the movie in which rajini comes in double role",
         "basha":"Don of a don movie,a cult hit",
         "enthiran":"rajini's scifi movie",
         "murattu kalai":"movie taken in paganeri",
         "muthu":"one of the thalaivar & sarath babu combination movie"}
print (films["muthu"])

bike = {"make":"royal enfiled","model":"himalayan","cc":400,"review":"mostly avg or bad"}
print (bike["model"])
print (bike["cc"])
#delete a element or delete a entire dictonary or cleare the elements in the dictionary
del(bike["review"])
# del(bike)
# bike.clear()
print (bike)
#getting the unpresent key value will result in error,in that case we can use get function
# print (bike["color"])
print(bike.get("color"))
#while True is used to make the user keep qasking the questions,unless he types quit
# while True:
#     x = input("enter any thalaivar's film name: ")
#     if x == "quit":
#         break
#     description = films.get(x)
#     print(description)
#     #the below piece of code will return error if we enter any unknown key value
#     print(films[x])

#same code is rewritten to print the custom message if the value doesnot exists in dictory

while True:
    x = input("enter any thalaivar's film name: ")
    if x == "quit":
        break
    if x in films:
        description = films.get(x)
        print(description)
        print(films[x])
    else:
        print ("{} - doesnot exists in dictionaryy".format(x))
 

Python Handling Binary ,Hex and octal Numbers - Day 6(posted next day)

its better to have a basic idea about binary and hexadecimal nos,since the computers deal with them, here are the basics

  
# #decimal numbers in binary
# for i in range(10):
#     print("{0:>2} in binary is {0:>8b}".format(i))
#
# print(0b1011)
# #hex decimal
# for i in range(257):
#     print("{0:>2} in hex is {0:>02x}".format(i))
#
# #hex multipliation
# x = 0x20
# y = 0x0a
# print(x*y)
# #operations like or,and,xor,add,subtract refreshed

#converting decimal to binary through program
# print(10//2)
# print(10%3)
# powers = []
# for power in range(15,-1,-1):
#     powers.append(2**power)
#     # print(powers)
# print(powers)
# x = int(input("enter any number less than 65535 to convert to binary \n"))
# for i in powers:
#     # print(i)
#     print(x//i,end ='')
#     x%=i
#the above program will work ,but to avoid the trialing 0's can use the below code
powers = []
for power in range(15,-1,-1):
    powers.append(2**power)
    # print(powers)
print(powers)
printing = False
x = int(input("enter any number less than 65535 to convert to binary \n"))
for i in powers:
    # print(i)
    bit = x//i
    if bit!=0 or i ==1:
        printing =True
    if printing==True:
        print(bit,end ='')
    x%=i